Breaching vs. Cutting, Arsenal Explosives question |
Breaching vs. Cutting, Arsenal Explosives question |
May 27 2008, 10:11 PM
Post
#1
|
|
Running Target Group: Members Posts: 1,109 Joined: 16-October 03 From: Raleigh, NC Member No.: 5,729 |
Greetings all. I've been familiarizing myself with the advanced explosive rules in Arsenal, and I've run into an issue. First off, let me quote a few relevant pieces of text:
QUOTE (Arsenal @ pg 93) Cutting requires far less explosives than breaching, but more preparation time. Makes sense, but I can't get it to work out in practice. Okay, lets say we are faced with a security door. That counts as Reinforced Material, so we have Structure Rating of 9, and an Armor Rating of 8. Let's also say that we have a drone carrying 200 foam explosive canisters, each packed with 1 kilogram of Rating 4 foam explosive. So if we decide to breach the door, lets figure out how much explosive it's going to take. Arsenal gives us the following: DV required = (Radius[m] x Structure Rating) + (Armor Rating ÷ 4) Explosive weight = (DV ÷ DV Multiplier ÷ Explosives Rating)squared in kg So to blow a 1 meter diameter hole, we need a DV of (.5 * 9) + (8 / 4) (4.5) + (2) 6.5 or 7 DV Let's say we are just putting the explosives on the ground, so the Multiplier is x1. The weight in kilograms is: (7 / 1 / 4) squared kilograms 3 kilograms So 3 kilos of rating 4 foam explosive will put a 1 meter diameter hole in our security door. Good 'nuff. So let's say instead of breaching it, we decide to try cutting it. We are going to attempt to cut a 1 square meter hole out of the door. We are still using rating 4 foam explosive, and we will shape it into four 1-meter lines. The DV formula for cutting is: (sqrt of kilos/meter)*(Rating of explosives) We also get 1 additional AP per net hit made on the demo extended test (assume no net hits, so no AP) The door can buy 2 hits from it's armor, effectively giving it 11 damage boxes. If we want to do 11 boxes of damage, we will need almost 9 KILOGRAMS PER ONE METER LINE!!! DV = (sqrt 9)*(4) DV = (3)*(4) DV = 12 Holy shit. You need a grand total of 36 kilograms of the same explosive to cut a 1meter square hole out of that security door, whereas you only need 3 kilos to blow a 1meter diameter hole. WTF??? Please tell me my math is wrong... [edit] My math WAS wrong, so I fixed it. But all the correction did was change the required mass of the breaching charge from 5 kilos to 3, exacerbating the problem with the cutting charge calculation. [/edit] |
|
|
Lo-Fi Version | Time is now: 13th January 2025 - 09:43 AM |
Topps, Inc has sole ownership of the names, logo, artwork, marks, photographs, sounds, audio, video and/or any proprietary material used in connection with the game Shadowrun. Topps, Inc has granted permission to the Dumpshock Forums to use such names, logos, artwork, marks and/or any proprietary materials for promotional and informational purposes on its website but does not endorse, and is not affiliated with the Dumpshock Forums in any official capacity whatsoever.