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> Help me figure out 2d6 result probabilities, Because twinking is important
Wounded Ronin
post Apr 24 2005, 06:09 PM
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OK, guys. According to http://www.chessandpoker.com/dice_strategy_guide.html the probability of rolling the following results with two six sided dice are as follows:

Result Probability
2 2.78%
3 5.56%
4 8.33%
5 11.11%
6 13.89%
7 16.67%
8 13.89%
9 11.11%
10 8.33%
11 5.56%
12 2.78%


Using these probabilities, how would I calculate the probability of rolling a 7 or greater?

I know that the probability of rolling an 11 and then a 12 would be the product of .0556 multiplied by .0278, but I forgot how to calculate the probability of rolling a 7 OR a 8 OR a 9, etc.
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