Ghouls: Do you tolerate them? Options

[Critias]

being so contagious you wouldn't want to shoot one that was to close either. The impact from a projectile could launch bodily fluids and/or flesh in an area surrounding the target...netting the same result as touching.

Not in the rules...but something interesting I thought about if you wanted to be a complete azz to your players.

Which is why you need to kill them with fire. Atomic fire, if you've got it, but regular old napalm or Fireball spells will do in a pinch.

[Stahlseele]

Setting Zombies . . erm, ghouls . . on Fire is a dumb idea . . all that will accomplish is the fact that the monsters coming straight at you are also on fire . .

[PirateChef]

Setting Zombies . . erm, ghouls . . on Fire is a dumb idea . . all that will accomplish is the fact that the monsters coming straight at you are also on fire . .

That's why you are backing up while you doit... everyone forgets that part. Keep running from the burning zombie until it stops moving.

[Falconer]

Nah... we need to arm all shadowrunners w/ pipebombs w/ time fuses and audio/visual ghoul attraction.

As well as everyone gets molotov cocktails.

Plus, everyone gets unlimited pistol ammo and wants to dual wield em.


Again, anyone else getting the urge to play Left4Dead?


Seriously... I can't see the disease being anything except this base on this level of virulence and spreading mechanism.

[Snow_Fox]

Nope, I don't tolerate working with naything that is potentially looking at me as a date/entree/recruit all at once.

[Critias]

Setting Zombies . . erm, ghouls . . on Fire is a dumb idea . . all that will accomplish is the fact that the monsters coming straight at you are also on fire . .

Setting things on fire is never a bad idea. If it's not working, you're just not burning hot enough.

[Ancient History]

Nope, I don't tolerate working with naything that is potentially looking at me as a date/entree/recruit all at once.

How do you feel about two out of three?

[Dumori]

The rules aint changed from RC as far as I can tell so this debate is either solved some place or a long time coming. However I will quote fluff to may be the correct way of treating this contact vector.

HMHVV III is the most virulent form of the virus, and it can
be spread with a bite, a scratch, even a mere touch if you’re unlucky
enough to have an open wound.

[Snow_Fox]

"When in doubt, fire and acid everytime." Peter Davidson as the 5th Doctor.

[The Jake]

Yes, thank you, this has been established. If and when (Ghost forfend) we have another edition and if (Ghost allows) I'm still there to throw my nickels in, it will be a point I will willingly bring up.

I think this is the best win this thread could have achieved. Thanks AH. (IMG:style_emoticons/default/smile.gif)

Until then, houserules win.

- J.

[toturi]

Since innoculations were a "loophole" that was closed, my question to the developers/writers would be - Are O-Cells the next "loophole" that will be closed?

Is the intention of the developers to turn Shadowrun into Zombierun?

[Shinobi Killfist]

Damn, I didn't tolerate me any ghouls before this. Nows I gots me a even better excuse to shoot first and alter the reports later.

[Zormal]

How do you feel about two out of three?

Mmmmm... I can think of several combinations of two that sound highly pleasant.

Thanks for your support, btw. Like The Jake said, it was 'the best win' (IMG:style_emoticons/default/wink.gif)

[Cardul]

Here is a question: Infectious Ghouls....how long do they live? Does anyone think that the non-infectious Ghouls mighthave started thinning out the numbers of the infectious ones? Or the ones that can still think, started thinning out the numbers of the feral ghouls, and isolating themselves from where they could accidentally infect others? It would seem that, if they want to survive as a group, they would be taking measures to make themselves less dangerous...

Or, at least those ones that want to show that ghouls are people too.

[Fuchs]

How does anyone detect an infectious ghoul? Do ghouls go "Oh, we don't know this new ghoul, let's kill him"?

[Stahlseele]

Probably. If not as a Safetymeasure, then to secure a new food-source.

[GreyBrother]

How they tell an infectious from a noninfectious apart? They just take a look at the aura, i'm sure you can detect such a thing with three or four hits.

[Machiavelli]

This enormous potential for infection is definitely something, the devs should reconsider in a future errata. It is far away from the basics we know since app. 20 years and would negate all developments the human/metahuman rights associations did since then. Nobody that is sane, would accept a single ghoul around him, not speaking of a whole ghoul nation. Just think about a ghoul, spitting on the ground, touching a glass in a bar, not knowing if he is infectious (maybe he doesn´t know it by himself)...and *poof* some days later every customer of this bar transforms. Not playable, unless you want to play Resident Evil Extinction.

[Marduc]

In augmentation p129

The number in parentheses is the minimum number of
Disease Resistance Tests the character must make. Even if a previous
test reduces the Power to 0, the character remains infected
and must make another test to resist the effects again after Speed
duration has passed, until the minimum number of tests have
been made.

Emphasis mine.

This clearly states that if you beat the disease power during the first ten tests you still need to take the remainder of the tests.

[Dancer]

As an alternative to killing with fire in cases where this may spread and cause further damage / lawsuits, how about entirely cocooning them in impervious material? Soem form of high-tensile freeze-foam or something, delivered high-pressure from a backpack sprayer.

[Stahlseele]

That would be one way to deal with them.
But not as easy and impressive as Napalm-Bombing their homes.
And you still need to get too close to them to apply the foam.

[toturi]

In augmentation p129

Emphasis mine.

This clearly states that if you beat the disease power during the first ten tests you still need to take the remainder of the tests.

Of course. But what power is the disease after you reduced its power to zero? To me, this is what is ambiguous.

[Marduc]

During the first ten tests the disease operates in an Accumulating Power mode, meaning that every test you must beat the base DV of the disease + any remaining power from the previous test.

example sequence
first test dv 8
save 4
second test dv 8 + 4 = 12
save 9
third test dv 8 + 3 = 11
save 11
fourth test dv 8 + 0 = 8
save 5
fifth test dv 8 + 3 = 11
ect.

[DuctShuiTengu]

For the following, P equals the base power of the disease (8 in the case of HMHVVIII), R is the remaining power from the prior test (that is, how far you fell short of making the threshold), and T is the total power for this interval

If the minimum duration has not passed:
T = P + R

If the minimum duration has passed:
T = 0 + R

P for HMHVVIII is 8. So, if your first test succeeds, reducing R to 0, what you get is the following:

T = 8 + 0

So, you're still looking at a Power of 8 for the second roll.

[toturi]

During the first ten tests the disease operates in an Accumulating Power mode, meaning that every test you must beat the base DV of the disease + any remaining power from the previous test.

example sequence
first test dv 8
save 4
second test dv 8 + 4 = 12
save 9
third test dv 8 + 3 = 11
save 11
fourth test dv 8 + 0 = 8
save 5
fifth test dv 8 + 3 = 11
ect.

Ah but "this accumulation only continues for a number of resistance tests as listed in parentheses after the Speed in the pathogen description". But that applies to the preceding sentence which states "if the pathogen's Power is not reduced to zero...".

Therefore what is the pathogen's power if its power is reduced to zero? The answer could be 0.

First test - Burn Edge - power 0
Since power reduced to zero, second paragraph does not apply, while the sentence that states number of minimum rolls still do, hence:
Second test Power 0
Third test Power 0
etc

If minimum duration has not passed, T = P+R(n) if R(n) !=0, where n>1
If R(n)=0, then P=0 until T>0

Therefore power of second roll is 0.