shadowrun d10, using d10 instead of d6 for SR Options

[KYA]

hi guys

since i started SR ive always had a problem with the dice rolling system:
difficulty 6 being twice as hard as 5, 7 being the same as 6 ...

ive seen a nice looking conversin to d8 , with the 8 being counted as 0
however, my group doesnt have any d8, only d6 from SR and d10 from some other gaming world with vampires and mages and stuff , so i thought about using the d10 for SR
howerver, even with the 10 counting as 0, this would affect the game balance

shor comparison chart, chance to succeed at diff. numbers from 1 to 18 with 1 die

[Quix]

:wobble: Actually I have no problem with your idea at all. I actually feel a little sheepish for not having thought of it myself since I have also experienced said game "with vampires and mages and stuff". My players regularly take the fact that in SR 6=7 and 12=13 to their advantage. If you can get the TN to 7 why sacrifice anything to get it to 6?

[D.Generate]

How is rolling a 6 twice as hard as rolling a 5 on a d6? Its a random number generating device there for any side of said dice has a 1 in 6 chance of coming up. As for the higher numbers 7 and so forth sure they are more difficult to get but then again if every test in Shadowrun was a success the game would become pretty damn boring and pointless to play. hell you might as well make it diceless at that point.

Tests are supposed to be hard sometimes, and shadowrunners are supposed to fail sometimes as is security meant to stop them. Its a dark and gritty game not a walk through a park.

Roll different dice if you must but try to come up with a better reason than the one you give. The system works fine as is.

[Ol' Scratch]

d10 is insane. A target number of 6 is supposed to be a tough one to hit, yet with a d10 it becomes as easy as a 4. Unopposed Tests in particular will become a nightmare of munchiness.

The variable chance of success at different target numbers is one of the charms of the Shadowrun system. You never really know what your chance of success is because the system is so non-linear that trying to calculate it on the fly requires a slide rule, so you're left just throwing the dice and hoping for the best.

If you want a mechanic that eliminates the 6=7 phenomenon that doesn't also require a complete reworking of target numbers, just assume that any roll of a 6 really means "5 + Reroll" whenever the target number is higher than 6. Only the probabilities for target numbers higher than 6 will be mildly affected, and then again with each increment of 6 beyond that.

But if you insist on using d10s, you're really going to need to revamp target numbers throughout the entire game because it grossly simplifies many of the most basic tests the game has.

[Ol' Scratch]

[D.Generate]

That makes sense Dr. Funk. But it still doesn't make it twice as hard sure its a bit harder but not twice. And if he uses his idea of 10=0 then that changes the everythign too since 1's are auto failures. so now your chances of failing outright become "twice" as much. Also the chances of a critical failure becomes higher. So really he's just creating more problems and not really solving anything.

[Austere Emancipa...]

[Bigity]

Yea, so the chance of rolling a success against a TN 6 is twice as hard as a TN5, but the chance of rolling a 5 is the same as rolling a 6. Probably just a little confusion there.

[Shockwave_IIc]

It's the difference of trying hit a golf ball 150 yards, or at least 150 yards.

And yes i agree with Dr Funk, if you change the dice you have to change the whole Tn system.

[John Campbell]

[Cynic project]

Or you could change the roll of six. Making each and evrytime you roll a six, you can reroll said die.If you beat the target number before you pick up the die and reroll it, go on as if ut was a new die. Making 6 and 7 different on a small scale. As in if you roll a six, you have a one in six chance of getting another six,and thus two succus from "one die".And if you are going for seven, when rolling a six, yes you will always get a succus, but you have to roll two more sixes to get two succuss.(At witch point you would have had three succusses with six)

A really luckily players rolls with one dice 6,6,6,4.
At TN 2-4, that is four succusses .He rolled over 2 with his 6.Seeing as he rolled over the TN he picks the die up and rolls it.It counted as a new die. He repeats this until he doesn't roll 6. You only get a new die, if the last number you rolled was hihger than your TN and the die is showing a 6.

AT 5-6, he would have gotten three succuses.

7-10, that is two.

11-20, that is one.

[JaronK]

If you want to fix the 6-7 problem in Shadowrun, it's really not very hard. Just make the rule of 6 be "re-roll the die, adding 5 to the result" instead of 6 to the result. This makes high target numbers a little harder to hit, so you might want to take them down a bit, but completely solves the 6-7 problem (since 6 = 6 then 1, but 7 = 6 then 2). You can't avoid the part about 5 being twice as easy to hit as 6... that's true in all dice configurations (on a d8 7 is twice as easy as 8, for example).

JaronK

[xizor]

well i like the idea because it makes the probabilitys so much neater :rotfl:
all those neat and tidy tens....
unlike those messy sixes...
for target numbers from 1 to 10 use -> 1-(TN-1)/10
for target numbers from 11 to 20 use -> (1-{TN-11}/10)X1/10
for target numbers from 21 to 30 use -> (1-{TN-21}/10)X1/100

this will provide the probability of sucess from a single die, rerolling on a 10

for all those messy sixes
for target numbers from 1 to 6-> 1-(TN-1)/6
for target numbers from 7 to 12-> [1-(TN-1)/6]X1/6
for target numbers from 13 to 18->[1-(TN-1)/6]X1/6X1/6
for target numbers from 19 to 24->[1-(TN-1)/6]X1/6X1/6X1/6
etc
this will provide the probability of sucess from a single die, rerolling on a 6

[Hida Tsuzua]

Another problem with the Rule of Six in Shadowrun now is that there is a small barrier between "extremely easy" to "insanely hard" for TNs. My group tried to expand the "difficult but possible" range of numbers though different ways ranging from simply increasing dice rolled to D8s. Finally keeping with the old D6 standard of Shadowrun, we created what I call the D56 system in that you reroll with a 5 or a 6 pushing allowable TNs up to 13s. Somewhere I have the charts about the chances of success and the like with the different systems if some are curious.

[xizor]

about rerolling on 5s and 6s, i actually tried working it out and i like the result.
it makes the higher target numbers not impossible :D
but seriously i really like what it does to the probability tables.
for example a TN of 12 has a 10.65% chance of success when you reroll 5s and 6s as opposed to a 2.8% chance of success rerolling 6s only

TN#/ reroll only on 6s/ reroll on 5s and 6s
2/83.3/83.3
3/66.7/66.7
4/50/50
5/33.3/33.3
6/16.7/33.3
7/16.7/30.6
8/13.9/25
9/11.1/19.4
10/8.3/13.9
11/5.6/11.1
12/2.8/10.6
i made it bigger so you could see the decimals without going blind

and an all new statistical hang up :wobble: not only does 6=7 but now 5=6 as well :grinbig:

i might go on and do the list up to 18 tomorrow but i have got tired of typing

any way i think that it offers a much different scale of hardness. not as destablilising as using a d10 but enough to make a large difference.

[Ol' Scratch]

It's funny you mentioned that. I once experimented with using that very mechanic with the Aptitude edge (you get to reroll 5's and 6's when using the listed skill) instead of the target modifier in a higher-power game and it worked well for the power level. I wouldn't use it in a standard game, though, since it seemed to greatly lessen the impact of common target modifiers.

[Hida Tsuzua]

It also helps we are complete redoing TNs along with everything else. :D While 5 is now the same as 6, all the other numbers have different chances of making it however slim (typically a 1% difference), as you can be rerolling off a 5 or 6 (or two or three).

[KYA]

all that 5/6 confusions could been easily solved by rereading my post:

[GrinderTheTroll]

You sir, are a glutton for punishment!

I don't see why you want to bother, you'd need to make alot of adjustments to the TN system to get it close to what SR uses. That and d6 are ALOT easier to find that d10 IMO.

I've considered using an d10-SR-type skill system, but it would be an different game.

[BitBasher]

Also you have to think... Dozens of hours of work for something that essentially ends up being the same system with a different die and slightly different probabilities. What's the point? It doesn't solve anyting it just moves it. a 10 is still twice as hard as a 9, same problem different breakpoint.

[Siege]

Having played a d20 system and a d10 system, using larger dice will give you the option of more flexibility in that you have a wider array of possible TNs.

Difficulty 5, 10, 15, 20, 25, 30+

Which allows for more situational modifiers if you so choose.

But if you're looking for complexity and detail, you might want to just use another game system entirely and drop the SR theme on it.

It'll be less pain in the long run.

-Siege

[Kagetenshi]

6/7 isn't a problem just like sub-2 TNs aren't a problem. Well, unless your game never uses modifiers. Sure, that 7 may be "good enough", but all it takes is a point of negative mod from something to kick it up to 8, while someone at 6 has that point of leeway.

~J

[Ol' Scratch]

The problem there is that it's odd that the guy facing a TN of 7 suffers a notable increase in his chance of failure for the exact same situational modifier that the TN 6 fellow is facing in the same situation. It works the same way in reverse, too. If they both have an Aptitude, TN 7 guy is having just as hard a time with his test as he did without the edge, while TN 6 guy has a significant improvement at succeeding in his.

But, again, the "6 = 5 + Reroll" houserule I've been using for a long while completely eliminates that without significantly impacting the value of target numbers or modifiers until you get to the really high numbers, at which point it's a lost cause anyway.

[GrinderTheTroll]

[Buck]

I was always bothered by TN 6 and 7 (12/13 etc.) having the same probability, but never did anything about it. But there are some really good ideas here, and I played around with them to get something I like.

Here's the idea: I reroll 5 and 6, but I make the 5 'weak' meaning that it counts only 1 + new roll. That means, I can score another success against TN 6 by rerolling the 5 and getting a 5 or 6. I can score another success against TN 7 by rerolling the 5 and getting a 6. From TN 8+ I only reroll the 6, because I can't get past 7 with the 5es.

What I get is a smaller difference between 5 and 6, and a difference between 6 and 7. All other probabilities stay the same (until 12/13, ...).

5 33.3
6 22
7 19.4
8 13.8

Contra: It's a little more complicated, of course. But not too much.