QUOTE (Tarantula @ Oct 3 2008, 08:09 PM)
All the pressure and energy in the cartridge does not get channeled into pushing the bullet. That is not the same amount of force the bullet would impart into the barrel when shot into it. Especially if the angle was very small, as it likely would be in these scenarios.
You're killing me here. First off, traditional ammunition has roughly 33% caloric efficiency. That means that 33% of the total energy (heat) output is transferred to the bullet. However, those gun ruptures were not 100% caloric efficient since it doesn't address the pure heat increase caused by the propellant. But to make you feel better, let's use that number.
Sheer logic would say that if 33% of the energy is in a bullet, then it would cause 33% of the devastation caused in those gun blow ups. Hey, that's still total failure! But at this point I'm pretty sure you won't take such simple logical extrapolation.
33% of the Mythbuster shotgun energy would still have deformed the barrel, only for ~2 inches in length instead of 6. Still a barrel kill. But wait, now we've concentrated that energy down to a 12g slug, which is 18.5 mm diameter or 268 mm^2. Ignoring the energy dissipated across the rest of the barrel and just taking the deformed area gives us 50 mm (2 inches) length x inner circumference (3.14 x 18.5) =2904 mm^2.
Hey, that means the shotgun slug has 11x the energy concentration, meaning it could crumple the barrel 11 times. Hey, since it was already yielding at 1x concentration and will rupture at 1.5x concentration (90ksi/60ksi) that means it will shatter 7 layers of barrel wall! Yay!
Okay, let's go back to your glancing blow arguement. First off, I've already defeated that using an AK47 shooting itself back
here. But you don't like theoretical examples. So let's go back to the shotgun.
Right now the shotgun slug is hurtling in with 11x the force required to completely collapse the barrel over one 268mm area. In reality you only need a few millimeters of deformation but why quibble?
To calculate the minimum glancing blow sufficient to collapsing force on the barrel, we use a classic right angle force triangle. Each side will be measured in barrel-collapses. The long side is 11x. The short side is 1x (minimum needed to make you happy).
To get the angle where the hypotenuse is 11 and one side is 1x we take the inverse sine of 1/11 and get 5 degrees. That means if the bullet comes in any more than 5 degrees off of the barrel alignment, it will still impart enough energy to completely collapse the barrel.
In the AK example it was less than 1 degree because the AK round was only dimpling the barrel sufficiently to ensure it wouldn't fire again.